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2y^2+9-y^2-17y+27=0
We add all the numbers together, and all the variables
y^2-17y+36=0
a = 1; b = -17; c = +36;
Δ = b2-4ac
Δ = -172-4·1·36
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{145}}{2*1}=\frac{17-\sqrt{145}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{145}}{2*1}=\frac{17+\sqrt{145}}{2} $
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